MATH SOLVE

4 months ago

Q:
# please awnser i fraction form 4 3/4 times 3 3/5 times 15

Accepted Solution

A:

Simplify the following:

(4 + 3/4) (3 + 3/5)×15

Put 3 + 3/5 over the common denominator 5. 3 + 3/5 = (5×3)/5 + 3/5:

(4 + 3/4) (5×3)/5 + 3/5 15

5×3 = 15:

(4 + 3/4) (15/5 + 3/5)×15

15/5 + 3/5 = (15 + 3)/5:

(4 + 3/4) (15 + 3)/5×15

15 + 3 = 18:

(4 + 3/4)×18/5×15

Put 4 + 3/4 over the common denominator 4. 4 + 3/4 = (4×4)/4 + 3/4:

(18×15)/5 (4×4)/4 + 3/4

4×4 = 16:

((16/4 + 3/4)×18×15)/5

16/4 + 3/4 = (16 + 3)/4:

(18×15)/5 (16 + 3)/4

16 + 3 = 19:

19/4×18/5×15

19/4×18/5×15 = (19×18×15)/(4×5):

(19×18×15)/(4×5)

15/5 = (5×3)/5 = 3:

(19×18×3)/4

The gcd of 18 and 4 is 2, so (19×18×3)/4 = (19 (2×9) 3)/(2×2) = 2/2×(19×9×3)/2 = (19×9×3)/2:

(19×9×3)/2

19×9 = 171:

(171×3)/2

171×3 = 513:

Answer: 513/2

(4 + 3/4) (3 + 3/5)×15

Put 3 + 3/5 over the common denominator 5. 3 + 3/5 = (5×3)/5 + 3/5:

(4 + 3/4) (5×3)/5 + 3/5 15

5×3 = 15:

(4 + 3/4) (15/5 + 3/5)×15

15/5 + 3/5 = (15 + 3)/5:

(4 + 3/4) (15 + 3)/5×15

15 + 3 = 18:

(4 + 3/4)×18/5×15

Put 4 + 3/4 over the common denominator 4. 4 + 3/4 = (4×4)/4 + 3/4:

(18×15)/5 (4×4)/4 + 3/4

4×4 = 16:

((16/4 + 3/4)×18×15)/5

16/4 + 3/4 = (16 + 3)/4:

(18×15)/5 (16 + 3)/4

16 + 3 = 19:

19/4×18/5×15

19/4×18/5×15 = (19×18×15)/(4×5):

(19×18×15)/(4×5)

15/5 = (5×3)/5 = 3:

(19×18×3)/4

The gcd of 18 and 4 is 2, so (19×18×3)/4 = (19 (2×9) 3)/(2×2) = 2/2×(19×9×3)/2 = (19×9×3)/2:

(19×9×3)/2

19×9 = 171:

(171×3)/2

171×3 = 513:

Answer: 513/2